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@ -1,4 +1,6 @@
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"""Open implementation of MonoLoco++ / MonStereo."""
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"""
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Open implementation of MonoLoco / MonoLoco++ / MonStereo
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"""
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__version__ = '0.2.3'
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__version__ = '0.5.0'
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@ -44,7 +44,7 @@ def cli():
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help='increase contrast to annotations by making image whiter')
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help='increase contrast to annotations by making image whiter')
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predict_parser.add_argument('--font-size', default=0, type=int, help='annotation font size')
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predict_parser.add_argument('--font-size', default=0, type=int, help='annotation font size')
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predict_parser.add_argument('--monocolor-connections', default=False, action='store_true',
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predict_parser.add_argument('--monocolor-connections', default=False, action='store_true',
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help='use a single color per instance')
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help='use a single color per instance')
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predict_parser.add_argument('--disable-cuda', action='store_true', help='disable CUDA')
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predict_parser.add_argument('--disable-cuda', action='store_true', help='disable CUDA')
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predict_parser.add_argument('--focal',
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predict_parser.add_argument('--focal',
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help='focal length in mm for a sensor size of 7.2x5.4 mm. Default nuScenes sensor',
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help='focal length in mm for a sensor size of 7.2x5.4 mm. Default nuScenes sensor',
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@ -1,24 +0,0 @@
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'''
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String of binary digits of length n,
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can we find out the probability that are at least 2 consequtive ones
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2 --> (1,1) out of 4 possibilities
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3 --> (0, 1, 1), (1, 1, 0) , (1,1,1)
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4 --> (0, 1, 1, 1) (1, 1, 1,1) (1,1, 0, 0)...
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'''
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n = 8
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def generate_strings(length):
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"""
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(0, 0, 0), (1, 0, 0), (1, 0, 1)
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"""
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def is_there_a_one(string):
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for idx, el in enumerate(string[:-1]):
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if el == 0:
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continue
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if string[idx+1] == 1:
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return 1
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return 0
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